我想我知道为什么科拉茨会这样做。
这个术语通常被称为“狂妄的宏大妄想”，所以请帮我一下：
3n走过同余类
+1步每个都不对齐
/2从未改变这个事实
累积互质性是阻止n重复的“记忆”。这在2^k下是不变的，使其能够在混乱中向前推进。耗尽模3的同余类迫使n变为2的幂；游戏结束。
我让AI证明这些事情，它做到了。我想是这样的。
那么唯一的问题就是1.5n能否足够快地增长残差向量，以超越穷举步行。我也问了AI这个问题，得到了一个一页的长文。我甚至不想打出来。
我可以用甜言蜜语让AI同意几乎任何事情，所以我陷入了困境。这是我所知道的唯一一个始终有深思熟虑对话的论坛，而我无法想出解决办法，我还有真正的工作要做。
这里有数学家吗？
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The normal term for this is "manic delusion of grandeur", so please help me out:<p>3n walks congruence classes
+1 steps each one out of alignment
/2 never changes that fact<p>Accumulating co-primeness is the "memory" that stops n from repeating. This is invariant under 2^k, which allows it to make forward progress through the chaos. Exhausting congruence classes mod 3 forces n to a power of 2; game over.<p>I asked AI to prove those things, and it did. I assume.<p>The only question then would be if 1.5n can grow the residue vector quickly enough to outrun the exhaustive walk. I asked AI that too, and got back a one page p-word. I'm not even going to type it.<p>I can sweet-talk AI into agreeing with damned near anything, so I'm stuck. This is the only forum I know with consistently thoughtful conversation, and I can't think my way out of this one, and I have real work to do.<p>Is there a mathematician in the house?